Optimal. Leaf size=128 \[ \frac{6 \sqrt [4]{5} \sqrt{-x^2+3 x-1} \text{EllipticF}\left (\sin ^{-1}\left (\frac{\sqrt{3-2 x}}{\sqrt [4]{5}}\right ),-1\right )}{\sqrt{x^2-3 x+1}}-\frac{4}{5} \sqrt{x^2-3 x+1} (3-2 x)^{3/2}-\frac{6 \sqrt [4]{5} \sqrt{-x^2+3 x-1} E\left (\left .\sin ^{-1}\left (\frac{\sqrt{3-2 x}}{\sqrt [4]{5}}\right )\right |-1\right )}{\sqrt{x^2-3 x+1}} \]
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Rubi [A] time = 0.0711873, antiderivative size = 128, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 8, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.364, Rules used = {692, 691, 690, 307, 221, 1181, 21, 424} \[ -\frac{4}{5} \sqrt{x^2-3 x+1} (3-2 x)^{3/2}+\frac{6 \sqrt [4]{5} \sqrt{-x^2+3 x-1} F\left (\left .\sin ^{-1}\left (\frac{\sqrt{3-2 x}}{\sqrt [4]{5}}\right )\right |-1\right )}{\sqrt{x^2-3 x+1}}-\frac{6 \sqrt [4]{5} \sqrt{-x^2+3 x-1} E\left (\left .\sin ^{-1}\left (\frac{\sqrt{3-2 x}}{\sqrt [4]{5}}\right )\right |-1\right )}{\sqrt{x^2-3 x+1}} \]
Antiderivative was successfully verified.
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Rule 692
Rule 691
Rule 690
Rule 307
Rule 221
Rule 1181
Rule 21
Rule 424
Rubi steps
\begin{align*} \int \frac{(3-2 x)^{5/2}}{\sqrt{1-3 x+x^2}} \, dx &=-\frac{4}{5} (3-2 x)^{3/2} \sqrt{1-3 x+x^2}+3 \int \frac{\sqrt{3-2 x}}{\sqrt{1-3 x+x^2}} \, dx\\ &=-\frac{4}{5} (3-2 x)^{3/2} \sqrt{1-3 x+x^2}+\frac{\left (3 \sqrt{-1+3 x-x^2}\right ) \int \frac{\sqrt{3-2 x}}{\sqrt{-\frac{1}{5}+\frac{3 x}{5}-\frac{x^2}{5}}} \, dx}{\sqrt{5} \sqrt{1-3 x+x^2}}\\ &=-\frac{4}{5} (3-2 x)^{3/2} \sqrt{1-3 x+x^2}-\frac{\left (6 \sqrt{-1+3 x-x^2}\right ) \operatorname{Subst}\left (\int \frac{x^2}{\sqrt{1-\frac{x^4}{5}}} \, dx,x,\sqrt{3-2 x}\right )}{\sqrt{5} \sqrt{1-3 x+x^2}}\\ &=-\frac{4}{5} (3-2 x)^{3/2} \sqrt{1-3 x+x^2}+\frac{\left (6 \sqrt{-1+3 x-x^2}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{1-\frac{x^4}{5}}} \, dx,x,\sqrt{3-2 x}\right )}{\sqrt{1-3 x+x^2}}-\frac{\left (6 \sqrt{-1+3 x-x^2}\right ) \operatorname{Subst}\left (\int \frac{1+\frac{x^2}{\sqrt{5}}}{\sqrt{1-\frac{x^4}{5}}} \, dx,x,\sqrt{3-2 x}\right )}{\sqrt{1-3 x+x^2}}\\ &=-\frac{4}{5} (3-2 x)^{3/2} \sqrt{1-3 x+x^2}+\frac{6 \sqrt [4]{5} \sqrt{-1+3 x-x^2} F\left (\left .\sin ^{-1}\left (\frac{\sqrt{3-2 x}}{\sqrt [4]{5}}\right )\right |-1\right )}{\sqrt{1-3 x+x^2}}-\frac{\left (6 \sqrt{-1+3 x-x^2}\right ) \operatorname{Subst}\left (\int \frac{1+\frac{x^2}{\sqrt{5}}}{\sqrt{\frac{1}{\sqrt{5}}-\frac{x^2}{5}} \sqrt{\frac{1}{\sqrt{5}}+\frac{x^2}{5}}} \, dx,x,\sqrt{3-2 x}\right )}{\sqrt{5} \sqrt{1-3 x+x^2}}\\ &=-\frac{4}{5} (3-2 x)^{3/2} \sqrt{1-3 x+x^2}+\frac{6 \sqrt [4]{5} \sqrt{-1+3 x-x^2} F\left (\left .\sin ^{-1}\left (\frac{\sqrt{3-2 x}}{\sqrt [4]{5}}\right )\right |-1\right )}{\sqrt{1-3 x+x^2}}-\frac{\left (6 \sqrt{-1+3 x-x^2}\right ) \operatorname{Subst}\left (\int \frac{\sqrt{\frac{1}{\sqrt{5}}+\frac{x^2}{5}}}{\sqrt{\frac{1}{\sqrt{5}}-\frac{x^2}{5}}} \, dx,x,\sqrt{3-2 x}\right )}{\sqrt{1-3 x+x^2}}\\ &=-\frac{4}{5} (3-2 x)^{3/2} \sqrt{1-3 x+x^2}-\frac{6 \sqrt [4]{5} \sqrt{-1+3 x-x^2} E\left (\left .\sin ^{-1}\left (\frac{\sqrt{3-2 x}}{\sqrt [4]{5}}\right )\right |-1\right )}{\sqrt{1-3 x+x^2}}+\frac{6 \sqrt [4]{5} \sqrt{-1+3 x-x^2} F\left (\left .\sin ^{-1}\left (\frac{\sqrt{3-2 x}}{\sqrt [4]{5}}\right )\right |-1\right )}{\sqrt{1-3 x+x^2}}\\ \end{align*}
Mathematica [C] time = 0.0233063, size = 76, normalized size = 0.59 \[ -\frac{2 (3-2 x)^{3/2} \left (\sqrt{5} \sqrt{-x^2+3 x-1} \, _2F_1\left (\frac{1}{2},\frac{3}{4};\frac{7}{4};\frac{1}{5} (3-2 x)^2\right )+2 x^2-6 x+2\right )}{5 \sqrt{x^2-3 x+1}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.252, size = 127, normalized size = 1. \begin{align*} -{\frac{1}{10\,{x}^{3}-45\,{x}^{2}+55\,x-15}\sqrt{3-2\,x}\sqrt{{x}^{2}-3\,x+1} \left ( 3\,\sqrt{ \left ( -2\,x+3+\sqrt{5} \right ) \sqrt{5}}\sqrt{ \left ( -3+2\,x \right ) \sqrt{5}}\sqrt{ \left ( 2\,x-3+\sqrt{5} \right ) \sqrt{5}}{\it EllipticE} \left ( 1/10\,\sqrt{2}\sqrt{5}\sqrt{ \left ( -2\,x+3+\sqrt{5} \right ) \sqrt{5}},\sqrt{2} \right ) \sqrt{5}-16\,{x}^{4}+96\,{x}^{3}-196\,{x}^{2}+156\,x-36 \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (-2 \, x + 3\right )}^{\frac{5}{2}}}{\sqrt{x^{2} - 3 \, x + 1}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (4 \, x^{2} - 12 \, x + 9\right )} \sqrt{-2 \, x + 3}}{\sqrt{x^{2} - 3 \, x + 1}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 25.7578, size = 41, normalized size = 0.32 \begin{align*} \frac{\sqrt{5} i \left (3 - 2 x\right )^{\frac{7}{2}} \Gamma \left (\frac{7}{4}\right ){{}_{2}F_{1}\left (\begin{matrix} \frac{1}{2}, \frac{7}{4} \\ \frac{11}{4} \end{matrix}\middle |{\frac{\left (3 - 2 x\right )^{2}}{5}} \right )}}{10 \Gamma \left (\frac{11}{4}\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (-2 \, x + 3\right )}^{\frac{5}{2}}}{\sqrt{x^{2} - 3 \, x + 1}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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